hi,

I need two similiar patterns.  One to check for a string of n digits to make sure that the first digit is not zero (0).

[1-9] [0-9] [0-9][0-9][0-9][0-9][0-9][0-9]etc

Then, I need to be able to have a comma delimited list of the above pattern.

[1-9] [0-9] [0-9][0-9][0-9][0-9][0-9][0-9],[1-9] [0-9] [0-9][0-9][0-9][0-9][0-9][0-9]etc

thanks!

jo

You were not very clear, so if my regexes are not what you were hoping for please explain in more detail and I will try to help.

This will match numbers of any length which do not start with 0:

\b(?!0)\d+\b

As for returning the matches in a comma-delimited list, you can replace each match with:

\0,

---

My regex-centric blog :: JavaScript regex tester

hi Stevezilla00,

thank you for your response.  the first part works beautifully... thanks.  i'm not sure how to use the next part though.  here's my code:

<script language="JavaScript">
function validateString(obj, formObj, formValue) {
var regex = /\b(?!0)\d+\b/;
return regex.test(formValue);
}
</script>

and here's a working example-> http://www.textit.com.au/x-testingJS.cfm

I need 61401345678,34678903,3489506023,23456677 to pass and

61401345678,34678903,0489506023,23456677 to NOT pass.

thanks for this.  your help is appreciated.

jo

try

^([1-9]\d*,)+[1-9]\d*$

61401345678,34678903,3489506023,23456677 should pass

61401345678,34678903,0489506023,23456677 will not

there should be no less than 2 numbers delimited by a comma for this to work

Sergei

Okay, I understand better now.

Sergei Z's regex is good. One thing, I'm pretty religious about putting anything in parens that I don't need captured as a backreference into a non-capturing group, like so:

^(?:[1-9]\d*,)+[1-9]\d*$

It will run just a tiny, tiny bit faster.

Two things about my previous regex...
1. The construct above without the negative lookahead will run a bit faster in some cases.
2. It looks for a number starting and ending at a word boundary, not at the very beginning and end of a string (e.g. "cat 123 dog" will return 123 instead of failing the match).

To address both these issues, change \b(?!0)\d+\b to this:

^[1-9]\d*$

---

My regex-centric blog :: JavaScript regex tester

thank you, thank you, thank you!  I'll give them all a shot and see what happens.

 

jo 

hi,

The single ones both work, but \b(?!0)\d+\b allows spaces and ^[1-9]\d*$ does not.  no spaces is better i think.

For the multiple comma delimited one, is it possible to check for one instance as well as multiples?

For example:

33434353434 should pass

or

33434343234,23234565565,2324235453,2234234343 should pass

thanks so much,

jo

try

(?:^(?:[1-9]\d*,)+[1-9]\d*$)|^[1-9]\d*$

it'll validate both

33434353434

and

33434343234,23234565565,2324235453,2234234343

alternatively try

^[1-9]\d*(?:(?:,[1-9]\d*)+)?$

hi Sergei,

thanks!  that works a treat :-)

jo